Can anyone help me solve this problem below:3x2−5x−2___________ <0x2−9

Answer:[tex]-\frac{1}{3} < x < 2[/tex] and -3 < x < 3Step-by-step explanation:The inequality equation is  3x² - 5x - 2 < 0 ⇒ 3x² - 6x + x - 2 < 0 ⇒ (x - 2)(3x + 1) < 0 Therefore, either (x - 2) > 0 and (3x + 1) < 0 ⇒ x > 2 and [tex]x < -\frac{1}{3}[/tex] which is not possible for any particular value of x. or, (x - 2) < 0 and (3x + 1) > 0 ⇒ x < 2 and [tex]x > -\frac{1}{3}[/tex] which is valid. So, the solution is [tex]-\frac{1}{3} < x < 2[/tex] (Answer) Now, another inequality is  x² - 9 < 0 ⇒ x² < 9 Therefore, -3 < x < 3 is the solution. (Answer)