5 months ago

24. The function f(t) = -16t^2 +20t +4 gives the height of a ball, in feet, t seconds after it is tossed.What is the average rate of change, in feet per second, over the interval [0.75, 1.25]

Accepted Solution

Answer:-12 feet per secondStep-by-step explanation:average rate of change over [0.75, 1.25] = [tex]\frac{f(1.25) - f(0.75)}{1.25 - 0.75}[/tex]f(1.25) - f(0.75) = 4 - 10 = -61.25 - 0.75 = 0.5[tex]\frac{f(1.25) - f(0.75)}{1.25 - 0.75}[/tex] = [tex]\frac{-6}{0.5}[/tex] = -12

ucutxmastrees

ucutxmastrees

24. The function f(t) = -16t^2 +20t +4 gives the height of a ball, in feet, t seconds after it is tossed.What is the average rate of change, in feet per second, over the interval [0.75, 1.25]

ucutxmastrees

ucutxmastrees

24. The function f(t) = -16t^2 +20t +4 gives the height of a ball, in feet, t seconds after it is tossed.What is the average rate of change, in feet per second, over the interval [0.75, 1.25]​

24. The function f(t) = -16t^2 +20t +4 gives the height of a ball, in feet, t seconds after it is tossed.What is the average rate of change, in feet per second, over the interval [0.75, 1.25]